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2^214^302 when divided by 9 f
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- ans is 4 i guess
bcoz... (((2^3)^21542)*(2^2)))/((2^3)+1) will give the remainder as 4*1=4
acc. to the remainder thm.. - 11 years agoHelpfull: Yes(24) No(5)
- 214*302=68628,
(2^1)%9=2
(2^2)%9=4
(2^3)%9=8
(2^4)%9=7
(2^5)%9=5
(2^6)%9=1
(2^7)%9=2
(2^8)%9=4 again leads to remainder 4 that is remainder cycle repeats so
we have to consider number of element in cycle that 6.
68628%6=2
that is 2nd element/position in remainder cycle=4,
{2,4(2nd),8,7,5,1}
answer is 4 - 11 years agoHelpfull: Yes(17) No(6)
- i think ans should be 5. 2^214^302= (((2^3)^71^302)*2^302)/9= ((-1)^71^302)*((2^3)^100*2^2)=-4 so 9-4=5.
correct me if i am wrong. - 11 years agoHelpfull: Yes(6) No(6)
- ans is 7...
- 11 years agoHelpfull: Yes(6) No(2)
- 4 is d correct ans
- 11 years agoHelpfull: Yes(4) No(4)
- May be your answer is correct avinash but 68628%6=0 definitely.
Kindly check. - 11 years agoHelpfull: Yes(4) No(0)
- can anyone explain it in datail? plz
- 11 years agoHelpfull: Yes(2) No(0)
- 4 is the remainder !!!
- 11 years agoHelpfull: Yes(1) No(0)
- 2^214^302 ~ 2^6 =4
- 11 years agoHelpfull: Yes(0) No(6)
- Ans is 4...
Lets See How-------
Step 1- 214/4= remainder 2
Step 2= 302/4= remainder 2
its means in the cycle of 2-------2nd term is 2 square(2^2)=4 is the right answer... - 9 years agoHelpfull: Yes(0) No(0)
- (2^214^302)/9
first of all find euler of 9 ...... E(9)=3^2=( 9*(3-1))/3=6
NOW (214^302)/6 if we divide 214 by 6 then we get either 4 remainder or -2 remainder also 302 divided by 6 we get 2 as remainder
((-2)^2)/6= 4/6
2^4/9= 16/9 = remainder 7 so ans is 7 - 8 years agoHelpfull: Yes(0) No(0)
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