if (1/a)+(1/b)+(1/c)= (1/a+b+c), (a*b*c)& (a+b+c) dos not equal to zero. And if x = (a+b)*(b+c)*(c+a)+(a+b+c) then which is true about x??

1-> x x>0 3->both 1 and 2nd

• It's option b. x>0;
  
  (1/a)+(1/b)+(1/c)=1/(a+b+c) --> Given
  
  Solving this equation we get.
  
  a*a*b + a*a*c + a*b*b + c*b*b + a*c*c + b*c*c + 2(a+b+c) = 0 ......(equation 1)
  
  x = (a+b)*(b+c)*(c+a)+(a+b+c) (Given)
  
  Solving this we get...
  
  x = a*a*b + a*a*c + a*b*b + c*b*b + a*c*c + b*c*c + 2(a+b+c) + (a+b+c)
  
  By equation (1)
  
  x = 0 + (a+b+c) and we knoe (a+b+c)!= 0
  so looking at the option option b is correct i.e. x>0
  
• 11 years agoHelpfull: Yes(15) No(1)
• option 1 is x0. actually that was a typing mistake
• 11 years agoHelpfull: Yes(1) No(0)