9.A tree of height 36 meters on the side of road of width 12 meter is broken in such a way that it forms a triangle with the road. what will be the length of the broken part?

• let one side =x then another side will be 36-x
  structure will be like this
  |
  x| 36-x
  |__
  12
  now x^2+12^2=(36-x)^2
  x=16
  hence one part will be 16m
  and another part will be 20 m
• 11 years agoHelpfull: Yes(20) No(1)
• answer is 20
  
• 11 years agoHelpfull: Yes(11) No(5)
• let the tree b broken at a point x
  so sides are:
  x,(36-x) and 12m
  Now, on analyzing we observe that it will form a right angled triangle
  Using hypotenuse rule:
  x^2+12^2=(36-x)^2
  on solving, we get:
  x=16 m
  other part (36-x)=20 m
• 11 years agoHelpfull: Yes(2) No(1)
• width of road=12 mtr
  let the broken part is of x meter then remaining part will be of 36-x meter.
  now we can apply theorem
  x^2=(12)^2 + (36-x)^2
  x=20
  this is required answer....
• 9 years agoHelpfull: Yes(1) No(0)
• Since the total height of tree is 36 m. Now let x m from top, the tree gets break. So the remaining height of the tree is (36-x) m.
  
  Now the broken part that is x m will act as hypotenuse in triangle where base is road (12 m) height is remaining tree length that is (36 - x) m and we have to find x. Now since the tree is perpendicular to the road so the tree, tree's broken part and road will form a right angled triangle. By Pythagoras Theorem we have,
  (Square of broken tree part length) = (Square of road length) + (Square of rest tree length after broken)
  
  i.e., square of x = square of 12 + square of (36-x)
  which yields
  x = 20 m
• 9 years agoHelpfull: Yes(0) No(0)
• H2=(36-h)2+144
  H=20
  
• 9 years agoHelpfull: Yes(0) No(0)
• broken part = 36-x m, rest = x m, 36-x,x,12 m should form a right angled triangle with hyp 36-x m. thus 12^2+x^2=(36-x)^2 => x=16 m => broken part = 36-x=20 m.
• 9 years agoHelpfull: Yes(0) No(0)
• X^2+12^2=(36-x)^2
  that implies x=20
• 7 years agoHelpfull: Yes(0) No(0)