In a 100m race, shyam runs at 1.66m/s. if shyam gives sujit a start of 4m and still beats him by 12 seconds,what is sujit's speed?

• 96/x-100/1.66=12
  1.32 m/s
• 11 years agoHelpfull: Yes(23) No(0)
• shyam gives sujit a start of 4m ,hence distance travel by sujit=96m
  
  time taken by sujit=time taken by shayam + 12
  dis travel by sujit/speed = dis travel + 12
  96/x =100/1.66 + 12
  x=1.32
  
  ans 1.32m/s
  
• 11 years agoHelpfull: Yes(10) No(0)
• time is constant
  therefore, (100/1.66)+ 12 = (96/x)
  x = 1.328 m/s
• 11 years agoHelpfull: Yes(2) No(0)
• 1204x = 1600,
  x=1.32
• 11 years agoHelpfull: Yes(2) No(0)