39. Two identical CIRCLES intersect so that their centres, and their points of which they intersect, form a square of 1cm. Find the area (in sq.cm) of the portion which is common to the two circles.

• area of sector= pi*r^2*angle/360= pi*r^2*90/360=pi/4
  area of triangle inscribed in the arc=0.5*b*h=1/2
  area of common portion=2[area of sector-area of triangle]
  =2[pi/4-0.5]=0.57
• 11 years agoHelpfull: Yes(38) No(1)
• area of sector= pi*r^2*angle/360 i.e 22*1^2*90/(7*360)= 11/14
  sum of area of two sector= 11/14*2= 11/7
  common area= (11/7-1)=4/7
• 11 years agoHelpfull: Yes(9) No(5)
• answer is pi/2 - 1
  i.e. 057
• 9 years agoHelpfull: Yes(1) No(1)
• Ans Area=2.57 sq.cm
• 11 years agoHelpfull: Yes(0) No(9)
• area of sector = π/4
  area of triangle formed = 1/2
  
  area = 0.569
• 11 years agoHelpfull: Yes(0) No(1)
• area of one circle =pi*r^2=pi
  1/4th of the area= 1/4*pi
  sum of 1/4th area of both the circles=2*1/4*pi=1/2*pi
  area of the square = 1^2=1
  common area =1/2*pi-1=(pi/2)-1
• 8 years agoHelpfull: Yes(0) No(0)