(61-a)(61-b)(61-c)(61-d)(61-e)=495
a,b,c,d,e are in ascending order
find a+b+c+d

• factor 495=11*5*3*3*1
  61-11=50
  61-5=56
  61-3=58
  61-3=58
  61-1=60
  so a+b+c+d=50+56+58+58=222 ans.
  
• 11 years agoHelpfull: Yes(39) No(18)
• ans :-> 290
  a = 50
  b = 52
  c = 60
  d = 62
  e = 66
• 11 years agoHelpfull: Yes(15) No(10)
• ans is 226.
  a=50
  b=56
  c=58
  d=62
  e=64
• 11 years agoHelpfull: Yes(10) No(5)
• Sorry that was mistakn
  @shilpi agarwal
  495= 3 * 3 * 5 * 11
  Now as in question it is expressed in multiple of five terms we have do that only.
  Also as a,b,c,d,e are in ascending order that means all are different.
  So we can't take both 3 as it is.
  So 495 = 3 * -3 * 5 * 11 * -1
  
  Comparing with the question a,b,c,d,e= 64,60,58,56,50
  Sum= 282
• 11 years agoHelpfull: Yes(6) No(3)
• can u please tell method for the solution?
• 11 years agoHelpfull: Yes(4) No(1)
• @shilpi agarwal
  495= 3 * 3 * 5 * 11
  Now as in question it is expressed in multiple of five terms we have do that only.
  Also as a,b,c,d,e are in ascending order that means all are different.
  So we can't take both 3 as it is.
  So 495 = 5 * 9 * 11
  We want 5 terms so 495=5 * 9 * 11 * 1 * -1
  Comparing with the question a,b,c,d,e= 62,60,56,52,50
  Sum= 280
• 11 years agoHelpfull: Yes(2) No(4)
• a=50
  b=56
  c=58
  d=62
  e=64
  we get 11*5*3*(-1)*(-3)=495
  a+b+c+d=226
  
• 11 years agoHelpfull: Yes(1) No(0)
• a=50 b=56 c=58 d=62 e=64 so we get 11*5*3*(-1)*(-3)=495... bingo..
• 11 years agoHelpfull: Yes(0) No(0)