Alok is attending a workshop ‘How to do more with less’ and today’s theme is working with fewer digits. The speakers discuss how a lot of miraculous mathematics can be achieved if mankind (as we as womankind) had only worked with fewer digits. The problem posed at the end of the workshop is ‘How many 6 digit numbers can be formed using the digits 1,2,3,4,5, (but with repetition) that are divisible by 4?’ Can you help Alok find the answer?
(a) 3906
(b) 3907
(c) 3125
(d) 1250

• for divisiblity by 4 rule is the last two digits of number should be divided by 4;
  so for 6 digit unit and ten digit must be 12,24,32,44,52 i.e 5 ways
  so,other 4 places are formed by 5^4 ways
  therefore the total ways are 5^4*5=5^5=3125
• 13 years agoHelpfull: Yes(10) No(1)
• 1 2 3 4 5 arrange in 12 24 32 44 52
  5 ways divisiablity rule of 4 is last two digits are divided by 4
  so there are 5^5 ways so ans is 3125
  
• 13 years agoHelpfull: Yes(2) No(0)