By using 1,2,3,4,5,how many 5 digit no. can be formed which is divisible by 4,repetation of no. is allowed??

• answer is 5^4 = 625
• 13 years agoHelpfull: Yes(7) No(15)
• step 1->the no divisible by only if it divisible by last 2 digit of no
  step 2->there for in this example that last 2 digit no are 12,24,32,44,52 ie total 5
  step 3-> - - - 1 2, - - - 24,same take other.....
  step 4--> use combination formula ncr=n!/r!(n-r)!
  step 5-->3 place remaining & available no 5 ie n=5
  step 6-->5c1 * 5c1 * 5c1=125
  step 7--->125*5=625
• 12 years agoHelpfull: Yes(4) No(1)
• units place can be filled by 2 ,4 as no. is to b divisible by 4
  since repitition of digits is allowed,
  hence no of ways to form 5 digit no. are 2*5*5*5*5 = 1250
• 13 years agoHelpfull: Yes(1) No(22)