) If there are 30 cans out of them one is poisoned if a person tastes very little he will die within 14hours so if there are mice to test and 24 hours to test, how many mices are required to find the poisonedcan?
a) 3 b) 2 c) 6 d) 1

• answer is 5 but it is not given in the otions
  
  reason: 2^(no. of mice)>(no. of cans)
• 13 years agoHelpfull: Yes(14) No(3)
• @all, here there is no data for mice, (i.e, time taken to die for mice
  ). here only given that, "if a person tastes very little he will die within 14hours". time taken to die for mice may not equal to time taken to die for a man.
  i think there is no mathematical logic over here. but TCS ask this type of stupid questions.
• 13 years agoHelpfull: Yes(12) No(1)
• Ans is 1
  
  if take 1 mouse...then we will give 1 drink within the period of let us take 15min....
  suppose if 4th can is poisiond then....time in which he dies is 15hrs...
  In this way we can judge which can is poisoned by calculating time interval
• 13 years agoHelpfull: Yes(8) No(9)
• @skant dude in question it is said that a mice can die within 14 hours and not after 14 hours so i think your logic fails over here....
  
• 13 years agoHelpfull: Yes(5) No(1)
• 1 mice & 14hrs 28mins are enough to get the result...
  At 1st min the mice tastes 1st can & dies at 14hr
  At 2nd min the mice tastes 2nd can & dies at 14hr.1Min
  At 3rd min the mice tastes 3rd can & dies at 14hr.2Min
  .
  .
  .
  At 29th min the mice tastes 29th can & dies at 14hr.28Min
  If the mice is till alive after 14hr.28Min then the poison will be in the 30th Can....
  
  So no death and result achieved in the last case...
• 13 years agoHelpfull: Yes(4) No(6)