IIT-JEE
Exam
Prove that, sin^8θ – cos^8θ = (sin^2θ – cos^2θ)
(1 – 2sin^2θ cos^2θ )
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IIT-JEE Other Question
Find the length of an arc of a circle of radius
5 cm subtending a central angle measuring
15º
Find the value of the following trigonometric
ratios -
(a) cos (–45) (b) sin (–30)
(c) cot (–60)