There are three frnds x, y , z gone to excursion with their girl frnds. there they wanted to find their weights but their GF’s are not accept to check their weight( all unnecessary data) . Then they check weights as x, y, z individually and then x and y, y and z, x and z ,then all(x,y,z). the last measure is 171. Then find the avg of all these seven measures.

• sum of 7 measures = x+y+z+(x+y)+(x+z)+(y+Z)+(x+y+z)= 4(x+y+z) =4*171
  
  Average of 7 measures = 4*171/7 = 97.714
• 13 years agoHelpfull: Yes(12) No(0)
• 4(x+y+z)/7 = 4*171/7
• 13 years agoHelpfull: Yes(6) No(0)
• (x+y+z)=171
  x+y+z+(x+y)+(y+z)+(x+z)=3(x+y+z)=3*171=513
  so
  513+171=684
  684/7=97.71428571
  
• 13 years agoHelpfull: Yes(2) No(0)
• 4*171/7=97.7
  
• 13 years agoHelpfull: Yes(0) No(0)