a game is played between two and one is declared as winner all the winner from the first round are played in the second round. all the winners from the second round are played in the third round and so on.if 8 rounds are played to declare one player as winner, how many players are played n the first round ?

• since its a knockout game
  so at evry round no. of players get halved
  in last/8th round there were 2 players
  7th round = 4 players
  6th round = 8 players
  5th round = 16 players
  similarly going till 1st round and doubling the no. of players we get 256 player in the beginning
  
  alternatively
  no. of players = 2^8 = 256
• 13 years agoHelpfull: Yes(6) No(0)
• 2^ no.of matches
  2^8=256
• 13 years agoHelpfull: Yes(4) No(1)
• 256 because 2 winner comes after playing their corresponding player....
• 13 years agoHelpfull: Yes(3) No(0)
• ans is 256. for players 2^n
• 13 years agoHelpfull: Yes(1) No(0)
• 256 is the answer.
  2^8 gives the answer.
• 13 years agoHelpfull: Yes(1) No(0)
• there are 8 peoples necessary to declare the winneer
• 13 years agoHelpfull: Yes(0) No(3)