AIEEE Exam

A box contains 3 white and 2 red balls. If we
draw one ball and without replacing the first ball,
the probability of drawing red ball in the second
draw is -
(A) 8/25 (B) 2/5
(C) 3/5 (D) 21/25

Read Solution (Total 1)

B. here there are two cases :
case 1: if frst ball chosen is white, then second has to be red -no, of cases are = 3C1*2C1
case 2: frst is red then secnd has to be red=2C1*1C1
total cases would be- 5C1*4C1=20
hence probability=(case1+case2)/total no. of cases
hence answer is=(3*2+2*1)/20 that is=2/5 (B)
11 years agoHelpfull: Yes(1) No(0)

AIEEE Other Question

The function y = e^–|x| is -
(A) continuous and differentiable at x = 0
(B) neither continuous nor differentiable at x = 0
(C) continuous but not differentiable at x = 0
(D) not continuous but differentiable at x = 0
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