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Numerical Ability
Permutation and Combination
How many three digit numbers can be formed using 2,3,4 and 5 with none of the digits being repeated
Read Solution (Total 14)
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- 1st position can be filled by 4 ways,2nd place can be filled by 3 ways and 3rd place can be filled by 2 ways.
total no. of ways= 4*3*2=24 - 11 years agoHelpfull: Yes(30) No(1)
- No.of ways of arranging is:total digits is 4 and are to be arranged in 3 places.Hence the total ways are: 4P3=24ways.
- 11 years agoHelpfull: Yes(4) No(0)
- ans is :4p3
- 11 years agoHelpfull: Yes(3) No(2)
- if the repeat is allowed then it will be....4*4*4=64ways
ans if the repeat is not allowed then 4*3*2=24ways - 10 years agoHelpfull: Yes(2) No(0)
- 4*3*2=24 ways as the first place is occupied in 4ways and 2 place in 3 ways and 3rd place in 2 ways.
- 11 years agoHelpfull: Yes(1) No(0)
- given four numbers 2,3,4,5 by using any of these numbers 3 at a time should form 3 digit number so the ans is 4p3=4*3*2*1=24
- 8 years agoHelpfull: Yes(1) No(0)
- 4*3*2=24 since first digit has 4 options, second digit-3,third digit-2.
- 11 years agoHelpfull: Yes(0) No(0)
- 24 ways
1st position can be filled in 4 ways,
2nd in 3 ways(as digits shouldn't be repeated),
and 3rd place in 2 ways (leaving the digits filled in 1st and 2nd position)
so 4*3*2=24 - 11 years agoHelpfull: Yes(0) No(0)
- 4p3 is anz
- 11 years agoHelpfull: Yes(0) No(1)
- ans 24
1st digit can be filled in 4 ways
2nd '' '' '' '' '' 3 '
3rd '' '' '' '' '' 2 "
so 4*3*2=24 - 11 years agoHelpfull: Yes(0) No(0)
- 3 digits can be taken from 4 numbers i.e(2,3,4,5) in 4c3 ways, and those 3 number can be arranged in 3! ways. so, the answer is 4c3*3!.
- 10 years agoHelpfull: Yes(0) No(1)
- 4 numbers... 3 digit number to be formed
4 * 3 * 2=24 ways without repeat. - 9 years agoHelpfull: Yes(0) No(0)
- 24 bcz 4*3*2 possibilities
- 6 years agoHelpfull: Yes(0) No(0)
- the sets are (2,3,4),(3,4,5),(4,5,2),(5,2,3).
3!+3!+3!+3!=4*6=24. - 6 years agoHelpfull: Yes(0) No(0)
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