Find the probability that a year containing 53 Sundays is a leap year.

• a leap year contains 366 days
  a week has 7 days so 366/7=52 weeks and 2 days
  the two days maybe one sunday or another day
  so probability is 1/7+1/7=2/7
• 11 years agoHelpfull: Yes(45) No(2)
• This question of probability given/total probability
  probability of having sunday in a leap year is 2/7
  probability of having sunday in non leap year is 1/7
  
  answer is 2/7 / 2/7+1/7 = 2/3
  answer is 2/3
• 11 years agoHelpfull: Yes(6) No(16)
• Number of days in leap year=366
  Extra number of days in leap year=366-364=2
  probability of sunday=2/7
• 11 years agoHelpfull: Yes(5) No(2)
• in a leap year there are 366days
  52weeks and 2 odd days
  in these two odd days sunday can occur twice
  hence total days =7
  probaility=2/7
• 11 years agoHelpfull: Yes(5) No(1)
• answer is 1/2
  since 52 weeks and 2 odd day
  out of which one is sunday
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• Nobody reads question carefully...
• 11 years agoHelpfull: Yes(2) No(1)
• ans is :3/7
• 11 years agoHelpfull: Yes(0) No(9)
• last 2 digits contains even no. and there are 3 even numbers in the given digits sso 3p2 ways
  now remaining 5 digits arranged in 4 places so 5p4 ways
  5!*3!= 720
  
• 11 years agoHelpfull: Yes(0) No(10)
• It is given to find out probability that a given year is a leap year if it contains 53 sundays.. And not the probability that a leap year contains 53 sundays.. So, P(year is a leap year given it contains 53 Sundays)=1/4
• 10 years agoHelpfull: Yes(0) No(0)
• chance of a year to be a leap year=1/4
  chance of sunday=1/7
  chance of a year to be a general year=3/4
  chance of sunday=2/7
  leap year--> (3/4* 1/7) + (1/4 * 2/7)=5/28
  
  therefore chance= (1/4 * 2/7)/(5/28)=2/5
• 10 years agoHelpfull: Yes(0) No(0)