Q. 15 Men take 21 days of 8 hrs. each to do a piece of work. How many days of 6 hrs. each would do if 21 women take. If 3 women do as much work of 2 men.

• 30.
  15m 168h ->1w
  14m 6x->1w
  solve this equn. u wil get the answer 30
• 13 years agoHelpfull: Yes(5) No(2)
• Find the no. of man-hrs to complete the job
  15 * 21 * 8 = 2520 man hrs:
  2 man-hrs = 3 women-hrs
  
  therefore
  1 women-hr = 2/3 man-hr:
  
  let d = no. days for these women to do the job
  21 * 2/3 * 6d = 2520
  84d = 2520
  d = 30 days
• 9 years agoHelpfull: Yes(4) No(0)
• 15M ->21days->8Hrs
  i.e 15M->21*8=168hrs
  now,
  3WOMEN=2MEN
  take a pair of 3 women in total no. of women i.e 21/3=7
  each 3 women=2 men
  7*2=14 men
  now
  1514=x/168
  i.e no. of hrs is inversely propositional to no. of workers
  therefore x=(168*15)/14=180
  180 hrs is total no. of hrs that women work
  now they work only 6hrs per day
  therefore 180/6=30
  ans:30days
  
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• 30 days
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• 30 days
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