IBM
Company
Numerical Ability
Number System
How many factors does 400 have?
a) 8
b) 10
c) 12
d) 15
Read Solution (Total 5)
-
- Ans:"15"
400 should be factorized as prime numbers.
So we can get, 400=(2^4)*(5^2).
The power of prime numbers are 4 and 2.
No of factors=(4+1)*(2+1)=5*3=15. - 11 years agoHelpfull: Yes(55) No(0)
- 15
2*2*2*2*5*5=400
so we h 4 no of 2 and 2 no of 5 bt 2^0 and 5^0 is also included
so in total we have 5*3=15 - 11 years agoHelpfull: Yes(13) No(0)
- an easier approach...!
fact:-all perfect square numbers have odd number of factors.
so 15 is the ans.. there is no need for prime factorization - 11 years agoHelpfull: Yes(11) No(0)
- 15 wil b d ans
- 11 years agoHelpfull: Yes(4) No(0)
- No of factors=(4+1)*(2+1)=5*3=15.
- 10 years agoHelpfull: Yes(0) No(0)
IBM Other Question
The number of 5-digit numbers that can be formed from 4,2,0,7 and 3 are:
A) 120
B) 96
C) 72
D) 24
today IBM qns on series i got.....
9, 3, 6, 21, 9, 12, 33, 15, 18, ?
3, 7, 10, 8, 4, 12, 0, 5, 5, 3, 2, ?
7, -35, -34, -3, 15, 16, ?
12, 3, 15, 14, 6, 19, 16, 9, 23, 18, 12, ?
7,-14,-4,15,-30,-20,-21...?
4,2,4,8,6,8,16,..