TCS
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Numerical Ability
Sequence and Series
which term in following does not belong to the sequence formed by rest
7,9,17,42,91,172,293.
options
a)17
b)9
c)91
d)42
Read Solution (Total 8)
-
- i am not sure but it should be b) 9
because from 17 on-wards the difference between two terms is the square of an odd number starting from 5 such 42 -17 = 25 --> 5^2
91-42 = 49 --> 7^2
172-91 = 81 --> 9^2
but starting two terms 7 and 9 doesn't make sense so they are different from the sequence. 9 is available in the option also. so b) 9 is the solution. - 11 years agoHelpfull: Yes(28) No(1)
- 7+1^2=8
8+3^2=17
17+5^2=42
42+7^2=91
91+9^2=172
172+11^2=293
So the answer will be 9 - 10 years agoHelpfull: Yes(7) No(0)
- wrong 9.
42 -17 = 25 --> 5^2
91-42 = 49 --> 7^2
172-91 = 81 --> 9^2 - 11 years agoHelpfull: Yes(5) No(1)
- I think the wrong is 9, since 7 is not given in option so i am 100% sure !!!
- 11 years agoHelpfull: Yes(2) No(2)
- in ths series only 9 hv a perfect square so 9 should be the ans
and bro i m 10000% sure;;;;;:) - 11 years agoHelpfull: Yes(1) No(0)
- 1^2 3^2 5^2 7^2 9^2 11^2 .. in place of 9 there would be 8
- 10 years agoHelpfull: Yes(0) No(0)
- 7+1^2=8
8+3^2=17
17+5^2=42
42+7^2=91
91+9^2=172
172+11^2=293
So the answer will be 9 - 10 years agoHelpfull: Yes(0) No(0)
- answer is option b -9 as it is clearly seen it forms an progression
- 9 years agoHelpfull: Yes(0) No(0)
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