what is the lcm of
(2^2011),(2^2011+1) and (2^2011+2)

• in 2^2011+1 is in form a^(odd)+b^(odd), which is always divisible by (a+b)
  so (2+1) = 3 in our case..
  .
  similarly 2^2011 + 2 can be written as 2(2^2010 + 1)
  AND concentrating on (2^2010 + 1) we simplify (4^1005 + 1) which is again in form a^(odd)+b^(odd), which is always divisible by (a+b)
  so in this case (4+1) = 5
  .
  and we know 2^2011 is least divisible by 2
  .
  .
  therefore the LCM of (2^2011) and (2^2011+1) and (2^2011+2) is 2*3*5 = 30
• 11 years agoHelpfull: Yes(1) No(0)
• lcm=(2^2011)*(2^2011+1)*(2^2010+1)
  =(2^4022+2^2011)*(2^2010+1)
  =2^6032+2^4022+2^4021+2^2011
• 11 years agoHelpfull: Yes(0) No(1)
• 2^2013 is the lcm of the given term, simply take the common out of them.
• 11 years agoHelpfull: Yes(0) No(1)