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A satellite is moving with a constant speed ‘V’ in a circular orbit about the earth. An object of mass ‘m’ is
ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its
ejection, the kinetic energy of the object is
Read Solution (Total 1)
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- Velocity for circular motion
V=√GM/R
R=GM/V^2
From above
Escape Velocity=√2GM/R^2 where R is same for both so
Escape velocity=V√2
KE=1/2 mV^2
=mV^2 - 10 years agoHelpfull: Yes(0) No(0)
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