IIT-JEE Exam

Two solid spheres A and B of equal volumes but of different densities dA and
dB are connected by a string. They are fully immersed in a fluid of density dF.
They get arranged into an equilibrium state as shown in the figure with a
tension in the string. The arrangement is possible only if
(A) dA < dF (B) dB > dF
(C) dA > dF (D) dA + dB = 2dF

Read Solution (Total 0)

IIT-JEE Other Question

A long insulated copper wire is closely wound as a spiral of
‘N’ turns. The spiral has inner radius ‘a’ and outer radius ‘b’.
The spiral lies in the XY plane and a steady current ‘I’ flows
through the wire. The Z-component of the magnetic field at
the centre of the spiral is A thin ring of mass 2 kg and radius 0.5 m is rolling without on
a horizontal plane with velocity 1 m/s. A small ball of mass
0.1 kg, moving with velocity 20 m/s in the opposite direction
hits the ring at a height of 0.75 m and goes vertically up with
velocity 10 m/s. Immediately after the collision

(A) the ring has pure rotation about its stationary CM.
(B) the ring comes to a complete stop.
(C) friction between the ring and the ground is to the left.
(D) there is no friction between the ring and the ground.