IIT-JEE
Exam
Two adjacent sides of a parallelogram ABCD are given by AB= 2ˆi +10ˆj+11kˆ
and AD= − ˆi + 2ˆj+ 2kˆ
. The
side AD is rotated by an acute angle α in the plane of the parallelogram so that AD becomes AD′. If AD′
makes a right angle with the side AB, then the cosine of the angle α is given by
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