Difference between two numbers is 4, and their product is 17. Then find the sum of their squares?

• let the nos. be a and b
  given, a-b=4 and a*b=17
  a^2+b^2=(a-b)^2+2*a*b
  putting the values,we get
  16+34=50
• 13 years agoHelpfull: Yes(22) No(9)
• Let the no be x & y
  x-y=4 & xy=17(given)
  x^2+y^2=(x-y)^2+2xy
  put the values,so
  x^2+y^2= 4^2 + 2*17
  x^2 + y^2= 50
• 9 years agoHelpfull: Yes(4) No(1)
• (x-y)^2=x^2+y^2-2*x*y=16
  hence x^2+y^2=50
• 9 years agoHelpfull: Yes(3) No(1)
• Say the numbers are x1 and x2
  Given x1-x2=4 --(i) and x1*x2=17--(ii)
  now x2=x1/1 putting this value in eq(i)we get x1^2-4x1-17=0.--(iii)
  Similarly from eq(i) x1=x2+4 putting this value in eq(ii)we get x2^2+4x1-17=0.---(iv)
  So by adding the equations (iii) & (iv) we get
  sum of their squares as 51
• 1 Month agoHelpfull: Yes(0) No(1)