Difference between two numbers is 4, and their product is 17. Then find the sum of their squares?

• let the nos. be a and b
  given, a-b=4 and a*b=17
  a^2+b^2=(a-b)^2+2*a*b
  putting the values,we get
  16+34=50
• 12 years agoHelpfull: Yes(22) No(9)
• Let the no be x & y
  x-y=4 & xy=17(given)
  x^2+y^2=(x-y)^2+2xy
  put the values,so
  x^2+y^2= 4^2 + 2*17
  x^2 + y^2= 50
• 9 years agoHelpfull: Yes(4) No(1)
• (x-y)^2=x^2+y^2-2*x*y=16
  hence x^2+y^2=50
• 9 years agoHelpfull: Yes(3) No(1)