IIT-JEE
Exam
Which of the following is correct ?
option
(A) a17 = a16 + a15
(B) c17 = c16 + c15
(C) b17 = b16 + c16
(D) a17 = c17 + b16
Read Solution (Total 1)
-
- a17 = a16 + a15
lets us consider the condition that the number which we write are the combination of 1&0
also consider that no two consecutive zeros comes together
consider
no of zeros 0 1 2 3 4 5 6 7 8 9
a15 1 +14c1 + 13c2 + 12c3+11c4+10c5+9c6+8c7 X X
a16 1 +15c1+ .............................+ 8c8 X
a17 1 +16c1+...............................+ 9c8 X
now let us consider the formula nCr+nC(r-1)=(n+1)Cr
=>1+15C1=16C1
therefore
a15+a16=a17
answer 1 satisfies
a17 = a16 + a15
- 10 years agoHelpfull: Yes(0) No(0)
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Bombardment of aluminum by α –particle leads toits artificial disintegration in two way.. Products X, Y and Z respectively are,
option
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