In how many ways a team of 11 must be selected from 5 men and 11 women such that the team must comprise of not more than 3 men ?
option
A. 1565
B. 2256
C. 2456
D. 1243

• Ans: B => 2256
  
  Maximum 3 men can be played which means there can be 0, 1, 2, 3 men in the team.
  (5C0*11C11)+(5C1*11C10 )+(5C2*11C9)+(5C3*11C8)=2256
  
• 11 years agoHelpfull: Yes(23) No(1)
• no. of ways of selctng (0,1,2,3)men in a team =(5c0*11c11)+(5c1*11c10)+(5c2*11c9)+(5c3*11c8)
  =1+55+550+1650
  =2256
• 11 years agoHelpfull: Yes(5) No(2)
• 3 men 8 women=(5c3*11c8)=1650
  2 men 9 women=(5c2*11c9)=550
  1 man 10 women=(5c1*11c10)=55
  0 man 11 women=(5c0*11c11)=1
  total=(1650+550+55+1)=2256
• 11 years agoHelpfull: Yes(3) No(1)
• 5C3*11C8 + 5C2*11C9 + 5C1*11C10 + 5C0*11C11 = 2256
• 10 years agoHelpfull: Yes(1) No(1)
• Take once 0 men, 1 men, 2 men,3 men
  So, (5C0*11C11)+(5C1*11C10 )+(5C2*11C9)+(5C3*11C8)
  => 1 + 55 + 550 + 1650 = 2256 Ans.
• 11 years agoHelpfull: Yes(0) No(1)
• no. of ways of Selecting (0,1,2,3)men in a team =(5c0*11c11)+(5c1*11c10)+(5c2*11c9)+(5c3*11c8)
  =1+55+550+1650
  =2266
  
  Its a dummy question in TCS..Check it out carefully
• 8 years agoHelpfull: Yes(0) No(0)