"LEADING" arrange it in such a way that at least two vowels always together...??

• first for (AEI)LDNG 5!*3!=720
  SECONDLY FOR (AE),(EI),(AI) + REMAINING LETTER 3(6!*2!)= 4320
  TOTAL 5040 ARRANGEMENTS
  
  
• 11 years agoHelpfull: Yes(32) No(9)
• The word ‘LEADING’ has 7 different letters.
  
  When the vowles EAI are always together, they can be supposed to form one letter.
  
  Then, we have to arrange the letters LNDG ( EAI ).
  
  Now, 5 (4 + 1 = 5 ) letters can be arranged in 5 = 20 ways.
  
  The vowles ( EAI ) can be arranged among themselves in 3 = 6 ways.
  
  Required number of ways = ( 120 × 6 ) = 720.
• 11 years agoHelpfull: Yes(9) No(7)
• 1. when all three are togethr
  5! * 3! = 120*6
  2. when any 2 are together from E , A , I
  6! * 2! * 3C2(choosing any 2 from given 3)= 1440*3
  so final = (1440*3)+(720).
  
• 11 years agoHelpfull: Yes(8) No(2)
• There are 2 possiblities i.e.
  1) Either all the three vowels will come together
  2) Or 2 vowels will comes together
  
  for 1st condition LDNG "EAI" = LDNG with "EAI" can arrange in !5 ways and then "EAI" can arrange in !3 ways therefore !5 * !3 = 120*6=720
  
  Now same for the second 1 LDNGI "EA" can arrange in !6 possible ways but "EA" only can arrange in !2 ways and therefore !6*!2= 720* 2= 1440
  
  Now the total no. of ways of arranging these 2 = 1440+720= "2160"
  
• 11 years agoHelpfull: Yes(7) No(9)
• THERE WILL BE TWO CASES:-
  CASE 1:- 2 VOWELS WILL BE TOGETHER 2*6!=1440
  CASE 2:- 3 VOWELS WILL BE TOGETHER 5!*3!=720
  
  1440+720= 2160 ANS.
• 11 years agoHelpfull: Yes(5) No(2)
• there are 7 ltrs...out of which we have to keep together A E I....we can keep it in 3! ways...now we can take aei & it's other format as one ltr so we have now 5 ltr....we can arrange it with 5! ways..
  so the total ways= 5!*4*
  =720 (ANS)
• 11 years agoHelpfull: Yes(1) No(5)
• Total no. of words using L,D,N,G and A,E,I will be 7! i.e.,5040.
  5040 contains three kind of words.
  1st = Three vowel together(like LAEIDNG,AEILDNG, etc)=720
  2nd = Two vowel together (like LAEDNGI,LAIDNGE, etc)=2880
  3rd = No vowel together (like LADENIG, ALEDNIG, etc)=1440
  
  Now,no. of ways when no vowels are together can be calculated from below
  *L*D*N*G* i.e.,5P3*4!=1440
  Hence,no. of ways to have atleast two vowels together=5040-1440=3600
  Required answer should be 3600
• 11 years agoHelpfull: Yes(1) No(2)
• for (AEI)LDNG it is 5!=120
  for (AEI)= 3
  120*3=360
  
  360 is the answer
• 11 years agoHelpfull: Yes(0) No(6)
• L(EA)DING=6 letters which acn b arranged in 6! ways..
  which is eqaul to 720 ways..
• 11 years agoHelpfull: Yes(0) No(3)
• This is 100% Correct Solution
  
  1) First take (AEI)+LDNG => 3! * 5 ! = 720
  2) (AE)+ILDNG => 2! * 6! = 1400 ( but this includes the possibility of AEI also )
  So 1440-720=720
  3) Similarly for EA and IE in case 2 we get 720 and 720..
  
  So the final answer will be 720+720+720=2160
• 11 years agoHelpfull: Yes(0) No(1)
• 6!*3C2=720*3=2160
• 11 years agoHelpfull: Yes(0) No(1)
• EAI L D N G
  3C2*2*6!=4320
• 10 years agoHelpfull: Yes(0) No(1)