A group of twelve persons is to be seated around a circular table. There are only two women in the group find the probability that there is at least three men between the two women.
option
1. 5/11
2. 7/12
3. 1/3
4. 2/9

• 5/11
  
  total 3m+2w=>5
  as it is a circular table it will be n-1
  given n=12
  therefore
  =(5)/(n-1)
  =5/(12-1)
  =5/11
• 10 years agoHelpfull: Yes(11) No(2)
• p(atleast 3 men b/w 2 women)= 1-p(no men or 1 men or 2 men btwn 2 womn)
  now the p(no men bw 2 wmn)=10!*2!/11!=2/11
  p(1 men bw 2wmn)=9!*10P1*2!/11!=2/11
  p(2 men bw 2wmn)=81*10P2*2!/11!=2/11
  so p(no men or 1 mn or 2 men bw 2 wmn)=2/11+2/11+2/11=6/11
  p(atlst 3 men bw 2 wmn)=1-6/11=5/11 Ans
• 10 years agoHelpfull: Yes(5) No(0)