If the root of the quadratic equation x^2-4x-log a(base3)=0 are real, then find the least value of a.

• 1/81 as,
  a>0 & D>=0
  D=b^2-4ac
  for real roots,
  (-4)^2 - (4*1*(-log a (base3))) >=0
  16 + 4 log a(base3) >= 0
  4 log a(base3) >= - 16
  log a(base3) >= -4
  a >= 3^ (-4)
  a>= 1/3^4
  a>=1/81
  
  
• 11 years agoHelpfull: Yes(4) No(0)
• 1/81 is d ryt ansr
• 11 years agoHelpfull: Yes(0) No(3)