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Numerical Ability
Probability
a, b, c are chosen randomly and with replacement from the set {1,2,3,4,5}. Find the probability that a*b+c is even.
Read Solution (Total 3)
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- a*b+c is even if
1. a is odd and b is even and c is even . (probability (3/5)*(2/5)*(2/5)) = 12/125
2. a is even and b is odd and c is even. (probability (2/5)*(3/5)*(2/5)) = 12/125
3. a is even and b is even and c is even (probability (2/5)*(2/5)*(2/5)) = 8/125
4. a is odd and b is odd and c is odd (probability (3/5)*(3/5)*(3/5)) = 27/125
total probability = 12/125 + 12/125 + 8 /125 + 27/125 = 59/125 :) - 10 years agoHelpfull: Yes(76) No(7)
- Three cases possible
(O,O,O)=3/5*3/5*3/5,
(E,E,E)=2/5*2/5*2/5,
(E,O,E)=2/5*3/5*2/5,
TOTAL = 59/125 Ans. - 10 years agoHelpfull: Yes(4) No(3)
- good job keep it up bro.....:)
- 10 years agoHelpfull: Yes(0) No(3)
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