a, b, c are chosen randomly and with replacement from the set {1,2,3,4,5}. Find the probability that a*b+c is even.

• a*b+c is even if
  1. a is odd and b is even and c is even . (probability (3/5)*(2/5)*(2/5)) = 12/125
  2. a is even and b is odd and c is even. (probability (2/5)*(3/5)*(2/5)) = 12/125
  3. a is even and b is even and c is even (probability (2/5)*(2/5)*(2/5)) = 8/125
  
  4. a is odd and b is odd and c is odd (probability (3/5)*(3/5)*(3/5)) = 27/125
  
  
  total probability = 12/125 + 12/125 + 8 /125 + 27/125 = 59/125 :)
• 11 years agoHelpfull: Yes(76) No(7)
• Three cases possible
  
  (O,O,O)=3/5*3/5*3/5,
  (E,E,E)=2/5*2/5*2/5,
  (E,O,E)=2/5*3/5*2/5,
  TOTAL = 59/125 Ans.
• 11 years agoHelpfull: Yes(4) No(3)
• good job keep it up bro.....:)
  
• 11 years agoHelpfull: Yes(0) No(3)