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Numerical Ability
Permutation and Combination
A group of twelve persons is to be seated around a circular table. There are only two women in the group find the probability that there is at least three men between the two women.
option
1. 5/11
2. 7/12
3. 1/3
4. 2/9
Read Solution (Total 5)
-
- 5/11
total 3m+2w=>5
as it is a circular table it will be n-1
given n=12
therefore
=(5)/(n-1)
=5/(12-1)
=5/11 - 11 years agoHelpfull: Yes(28) No(12)
- 1)5/11(ans)
total 3m+2w=>5
as it is a circular table it will be n-1
given n=12
therefore
=(5)/(n-1)
=5/(12-1)
=5/11 - 11 years agoHelpfull: Yes(5) No(10)
- there can be three cases when no. of men between two women are 0,1 and 2 which are not acceptable means probability of having less than 3 men between two women is 3/12.
so, probability of having atleast 3 men will be 1 - 3/12 = 1/3
option 3. is the correect answer - 11 years agoHelpfull: Yes(4) No(16)
- ans) 2. 7/12
- 11 years agoHelpfull: Yes(3) No(9)
- (a) 5/11
Regardless of how the two women are seated, there are the same number of possible arrangements for the 10 men in the remaining 10 seats (10! arrangements, in fact). So each of the possible relationships between the seats of the two women is equally probable.
Thus, we can arbitrarily pick the position of one of the women and simply consider how many, of the 11 other seats, are far enough away that there are at least 3 men in between?
There are 2 seats adjacent to the first woman (no men in between),
2 seats one position further away (one man in between),
2 seats one more position further away (two men in between),
2 seats with 3 men in between (the shortest way; the other 7 men are around the other direction),
2 seats with 4 men in between,
and 1 seat with 5 men in between (in each direction).
So 5 out of the 11 seats have at least 3 men between the two women in both directions around the table.
- 10 years agoHelpfull: Yes(0) No(0)
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