4,64,1,1,3,27,2,?
Please give me a proper solution with xplanation.

• pair the numbers i.e (4,64),(1,1),(3,27),(2,_)
  so 4^3=64 , 1^3=1 ,3^3=27 ,so ,2^3=8
  8 is the ans.
• 11 years agoHelpfull: Yes(53) No(0)
• this series is like
  a,a^2,b,b^2....
  ans.8
• 11 years agoHelpfull: Yes(6) No(5)
• 8= because second one is cube of first one
• 11 years agoHelpfull: Yes(3) No(0)
• 8 second number is square of first number...
  
• 11 years agoHelpfull: Yes(2) No(1)
• 4*(4 pow 2)=64
  1*(1 pow 2)=1
  3*(3 pow 2)=9
  2*(2 pow 2)=8
  
• 11 years agoHelpfull: Yes(1) No(4)
• see pairs (4,64); (1,1); (3,27)
  4*4*4=64
  3*3*3=27
  the answer is 8.
• 11 years agoHelpfull: Yes(1) No(0)
• the series is as
  (4,64),(1,1),(3,27),(2,_)
  so the solution is 2^3=8
• 11 years agoHelpfull: Yes(1) No(0)
• 4^3=64,
  1^3=1,
  3^3=27,
  2^3=8
• 11 years agoHelpfull: Yes(1) No(0)
• 4 4^3=64
  1 1^3=1
  3 3^3=27
  2 2^3=8
  so ans is 8
• 11 years agoHelpfull: Yes(1) No(0)
• I think ans will be 2
• 11 years agoHelpfull: Yes(1) No(4)
• 4^3=64
  1^3=1
  3^3=27
  2^3=8
• 10 years agoHelpfull: Yes(0) No(0)