6 red chip 7 green and 8 blue chip in a bag If 5 are drawn with replacement then what

favourable event=6c3*15c2+6c4*15c1+6c5*15c0
total event=21c5
i.e, probability=(6c3*15c2+6c4*15c1+6c5*15c0)/21c5
11 years agoHelpfull: Yes(48) No(11)

(6/21*6/21*6/21*15/21*15/21) for 3 red chip
(6/21*6/21*6/21*6/21*15/21) for 4 red chip
(6/21*6/21*6/21*6/21*6/21) for 5 red chip
now add all nd u will get d answer as 75816/4084101 = 0.018
11 years agoHelpfull: Yes(22) No(4)
6c3*15c2+6c4*15c1*6c5/21c5
11 years agoHelpfull: Yes(4) No(3)
on solving it is 0.11 answer..
11 years agoHelpfull: Yes(4) No(0)
@ Mohit- this ques is the case of replacement. y are u neglecting it?
11 years agoHelpfull: Yes(3) No(1)
favourable event=6c3*15c2+6c4*15c1+6c5*15c0
total event=21c5
i.e, probability=(6c3*15c2+6c4*15c1+6c5*15c0)/21c5
10 years agoHelpfull: Yes(1) No(1)
total no of fav cases=6c3.7c1.8c1+6c3.7c2+6c3.8c2
total no of cases=21c5
so probability=no.of fav cases/no.of total cases
11 years agoHelpfull: Yes(0) No(7)

6 red chip,7 green and 8 blue chip in a bag. If 5 are drawn with replacement,then what is the probability that atleast 3 are red.