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find the last 2 digit of 1122^1122
Read Solution (Total 14)
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- ANS WILL BE 84..
- 11 years agoHelpfull: Yes(22) No(2)
- 44 is the ans.
- 11 years agoHelpfull: Yes(15) No(9)
- divide the power 1122 by 4
it will be in the form 4n+2, 2 is the remainder, then unit digit of the base^2(rem) gives unit digit 4 and the 10th digit x 2 gives 10th digit number 4
so we have now 44.(ans) - 11 years agoHelpfull: Yes(2) No(1)
- do u know ans is 04............hahaha
- 10 years agoHelpfull: Yes(2) No(0)
- 2^20 gives 76 in end. 76*76 is also 76
1122! has lot of zeroes at the end, divisible by 20
thus 1122^(20 * sum other number)=76 as last two digits - 11 years agoHelpfull: Yes(1) No(4)
- last digit=1122^1120*1122^2=8
nd 2nd last is 2 ans is 28 - 11 years agoHelpfull: Yes(1) No(0)
- 1122^1122
for last 2 digit 22^1122=(11^2)^561=(121)^561=21^561
so the ans is 21
(as unit digit will always be 1 and 2nd digit is found 2*1=2 so 21) - 11 years agoHelpfull: Yes(0) No(17)
- 42 is the answr
- 11 years agoHelpfull: Yes(0) No(13)
- 42 will be the ans
- 11 years agoHelpfull: Yes(0) No(12)
- 22^2=84
and after dat evry 22^10 gives 84 back at last 2 digits... - 11 years agoHelpfull: Yes(0) No(0)
- 4 is the last digit.
last digit of 1122 is 2 so 1122/4 gives remainder of 2.
for remainder 1 - last digit is 2
for remainder 2 - last digit is 4
. 3 - 8
0 - 6
.
. - 11 years agoHelpfull: Yes(0) No(0)
- 76 is the answer.......
- 10 years agoHelpfull: Yes(0) No(4)
- ans is 04
- 10 years agoHelpfull: Yes(0) No(0)
- ans is 04.
- 10 years agoHelpfull: Yes(0) No(0)
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