7. In a given right angled triangle ABC, rt. angle at B, D is a point on BC such that AD is perpendicular to BC. If AD=32 and CD=18. Find the radius of the circle circumscribing the triangle ABC

• ans. 18.3575
  as we know that any triangle drawn upon the diameter is a right angle.
  Now a/c to question the points B and D must be same.
  so finding the hypotenuse we get it to be = root(1024+324) = 36.715
  so dividing it by 2 we get the soln as 18.3575
• 10 years agoHelpfull: Yes(22) No(1)
• HREE 32 is the diameter of circle.
  so radius,32/2=16(ans)
• 10 years agoHelpfull: Yes(3) No(9)
• as B and D are the same point so AD =32 and CD=18
  we can find AC=36.71 it will also be the diameter.so radius =18.357
• 10 years agoHelpfull: Yes(3) No(0)
• In a Right Angled Triangle ABC and rt. angle at B then AB is perpendicular to BC
  thus B and D are same points. therefore we have AD=AB=32 and BC=DC=18 where
  AC is Hypothesis then AC=36.7151,Radius is 18.357
  
• 10 years agoHelpfull: Yes(2) No(0)
• the line AB and AD concide to each other so by formula r=AD+CD-UNDERROOT(32*32+18*18)whole divided by 2 so ans 6.64
• 10 years agoHelpfull: Yes(0) No(4)
• by que, as B is right angle, B and D coincides.
  so hypo= sqrt((32*32)+(18*18))=36.71
  radius= 18.35 units
• 10 years agoHelpfull: Yes(0) No(0)
• B and D are the same point so AD =32 and CD=18
  we can find AC=36.71 it will also be the diameter.so radius =18.357
• 10 years agoHelpfull: Yes(0) No(0)