TCS
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Numerical Ability
Percentage
) If the numerator of a fraction is increased by 25% and denominator decreased by 20%, the new value is 5/4. What is the original value?
a) 3/5
b) 4/5
c) 7/8
d) 3/7
Read Solution (Total 9)
-
- let numerator is x nd denominator is y.if we increase x by 25% den it will be 125x/100 nd if u decrease y by 20% thn value will be 80y/100. then new value is 125x/80y=5/4 .or x/y=4/5. hence d answr is - b)4/5
- 13 years agoHelpfull: Yes(20) No(0)
- let x/y be the original value
then acc to qustn : (x+.25x)/(y-.2y) = 5/4
==>(1.25x/0.8y)=5/4
==>x/y= 4/5 - 13 years agoHelpfull: Yes(8) No(2)
- answer is 4/5
- 13 years agoHelpfull: Yes(3) No(1)
- b
(1.25X)/0.8Y = 5/4
--> X/Y = 4/5 - 9 years agoHelpfull: Yes(1) No(0)
- LET US GO BY VERIFYING OPTIONS
25% OF 4 IS 1
20% OF 5 IS 1
SO ANSWER IS 4/5 - 8 years agoHelpfull: Yes(1) No(0)
- (x*125)/(80*y)=5/4 solve and ans=4/5
- 9 years agoHelpfull: Yes(0) No(0)
- ans :4/5
consider numerator and demoninator are x,y then
x+(x*25/100) 5
------------------ = -------
y-(y-20/100) 4
if we solve it we will get 4/5 x=5 and y=4 - 8 years agoHelpfull: Yes(0) No(0)
- b) 4/5
x= numerator. x= 5/1,25 (as increase was 25%) y=denominator, y=4/0.80(as decrease was 20%)
on equating x/y=4/5 - 8 years agoHelpfull: Yes(0) No(0)
- (x*125)/(y*80)=5/4.... on solving x/y=4/5
- 7 years agoHelpfull: Yes(0) No(0)
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