) In the class of 40 students, 30 speak Hindi and 20 speak English. What is the lowest possible number of students who speak both the languages?

(a) 5

(b) 20

(c) 15

(d) 10

(e) 30

• H | E=40
  H=30
  E=20
  NOW-> H | E = H + E - H & E
  SO--> H & E = 30+20-40
  =50-40
  =10(ANSWER)
  
  
• 12 years agoHelpfull: Yes(9) No(2)
• A℧B=A+B-AΩB
  30+20-40=10
• 12 years agoHelpfull: Yes(7) No(1)
• 10...aUb=n(a)+n(b)-a(intesection)b
• 12 years agoHelpfull: Yes(4) No(1)
• ans is 10.becau the logic says .but y should it be the least.it should be unique
• 12 years agoHelpfull: Yes(4) No(2)
• AUB = A + B - A"intersection"B
  40 = 30 + 20 - A"inters."B
  A"inter"B =50-40 = 10
• 12 years agoHelpfull: Yes(3) No(3)
• 10 is maximum possible number of students who can speak both hindi and english according to options given the answere will be 5 .
• 9 years agoHelpfull: Yes(2) No(2)
• 40-30-20=-10 so who speak both the lang will b 10
• 7 years agoHelpfull: Yes(1) No(0)
• if out of 40 , only 30 speak hindi and 20 speak english
  then both= ???????
  
  Easy method is
  30/40= 3/4
  then
  20/40=1/2
  then
  multiply 2*3+4=10
• 5 years agoHelpfull: Yes(1) No(1)
• 10
  if first 30 speak hindi and the last 20 speak english then only 10 students remain in common.therefore the least number of students is 10
• 8 years agoHelpfull: Yes(0) No(1)
• (30+20)-40=10
• 8 years agoHelpfull: Yes(0) No(0)
• n=n(H)+n(E)-n(H^E)
  40=30+20-n(H^E)
  n(H^E)=10
• 3 years agoHelpfull: Yes(0) No(0)