distance of the z intercept from the x intercept in ax+by+cz+d=0?

• ax + by + cz + d = 0
  
  At the z-intercept, 'x' and 'y' are both zero.
  
  cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).
  
  At the x-intercept, 'y' and 'z' are zero.
  
  ax + d = 0 --> x = -d/a --> The x-intercept is the point (-d/a, 0, 0).
  
  The distance between the points (0, 0, -d/c) and (-d/a, 0, 0) is
  
  sqrt[ (-d/a)2 + (-d/c)2 ] = sqrt (d2/a2 + d2/c2) = d sqrt(1/a2 + 1/c2)
• 13 years agoHelpfull: Yes(19) No(0)