A bag contains 10 red and 4 green balls whereas a second bag contains 9 red and 5 green balls. A ball is selected randomly from one of bag. What would be the probability of selecting a ball from first bag? It is given that the selected ball is necessarily red.

• this is the case of BAY'S theorm---
  
  then,solution will be:- first select first bag then select the red ball from that bag upon total probilbity-
  
  (1/2*10/14)/(1/2*10/14+1/2*9/14)
  =10/19
  
  this is the right solution
  
• 13 years agoHelpfull: Yes(9) No(5)
• probab. of selecting 1st bag=1/2
  probab. of picking a red ball from 1st bag=10c1/14c1
  so reqd. probability=1/2*10/14=5/14....
• 13 years agoHelpfull: Yes(5) No(1)
• Answer is directly calculated by :
  Total no. of red balls = 19
  Total no. of red balls in first bag = 10
  hence Probability=10/19
  
• 12 years agoHelpfull: Yes(1) No(2)
• what r the conditins in which bays theorm should be apply?
• 13 years agoHelpfull: Yes(0) No(0)
• 5/14
  since prob to choose first bag is 1/2 and then to choose red ball is 10/14
• 12 years agoHelpfull: Yes(0) No(0)