How many 8 digits number can be formed with repitition by using 1,2,3,4,5 which are divisible by 4 ?

• 5^7 as we can fill the first 6 digits in 5^6 ways with repetiton and then for the last two digits we have only 5 combinations with the given numbers that is 12,24,32,44 and 52 so we get 5^7 combinations
• 11 years agoHelpfull: Yes(31) No(0)
• sorry....5 possibility r there for filling last two digit(12,24,32,44,52)
  sol=5^6*5=78125
• 11 years agoHelpfull: Yes(11) No(2)
• sorry missed 52..the ans 5^7
• 11 years agoHelpfull: Yes(7) No(1)
• ans. 62500
  a no to be divisible by 4 should have the last two digits divisible by 4
  there can be 4 such no(24,44,32,12)
  rest 6 place can be filled by 5 ways.
  thus soln = 5^6*4 = 62500
• 11 years agoHelpfull: Yes(4) No(10)
• the first 6 places can be filled with 5^6,we have to check for the last two digits
  for divisibilty by 4 they must be divisible hence at the 8th place we can have only 2 & 4 hence
  for 2(as 8th digit)
  (5^6)*3*1(as the 7th place can be filled with 1,3,5 only)
  for 4(as 8th digit)
  (5^6)*2*1(as the 7th place can be filled with 2,4 only)
  hence (5^6*3*1)+(5^6*2*1)=78125
• 11 years agoHelpfull: Yes(3) No(0)
• suppose there r 8 places to be filled by given no. with repition
  for no to be divisible by 4 it must contain 12, 24, 32, 44, 52 at last i.e. if last two digits r divisible by 4 then no. is divisible by 4
  possible no. r now 6 places left suppose solve for no. contain 12 at last= 5^6 i.e repition allowed but here total possible no. possible other than 12 including 12 at last r= 5^6 * 5= 5^7 is answer
• 11 years agoHelpfull: Yes(3) No(0)
• answer is 5^7
• 11 years agoHelpfull: Yes(2) No(0)
• A no is divisible by 4 if last two digits r divisible by 4
  so,here total 4 possibility(12,24,32,44)
  so,last two digits r collectively filled by 4 ways....
  rest 6 places r filled by 5 ways each(becaus repeation is allowed)
  so,solution= 5^6*4=62500
• 11 years agoHelpfull: Yes(1) No(1)
• A no is divisible by 4 if last two digits r divisible by 4
  so,here total 4 possibility(12,24,32,44)
  so,last two digits r collectively filled by 4 ways;
  repeation is allowed so
  rest 6 places r filled by 5 ways each
  so,solution= 5^6*4=62500
• 11 years agoHelpfull: Yes(1) No(2)
• rite ans ...........5^7.
• 11 years agoHelpfull: Yes(1) No(0)
• the answer is 375000.
  for the first six places there are . 5 options for each place and for the alst two there are 24 options( nly 24 no. from 1-99 which are divisible by 4 ).
  so total no. of permutations = (5^6)*24 = 375000
• 11 years agoHelpfull: Yes(0) No(7)
• there are 5 numbers 1,2,3,4,5
  we required 8 digit number
  so
  5^8-1=5^7
• 11 years agoHelpfull: Yes(0) No(1)