one the planet oz ,there are 8 days in a week sunday to sat and anoter day called oz day .there are 36 hrs a day n each hr has 90 min n each min 60 sec.as on earth ,hour hand covers the dial twice every day .fint te apprximate angle betwn te hands of clock on oz when time is 14.40am?any simple way to solve
options
83
74
129
65

• pos of hr hand at 14.40am = pos at 14.00am + offset of 40mins
  = 360deg/18hrs * [14hrs + (40/90)hrs]
  = 288.89deg
  
  pos of min hand after 40 mins = 360deg/90min * 40min
  = 160deg
  
  => relative position = 289 - 160
  = 129deg
• 13 years agoHelpfull: Yes(6) No(0)
• ANS: 129 deg
  
  36 hours a day mane the clk will be of 18 hours.
  18 hours covrs 360 deg
  Thus 1 hour covrs 20 deg
  14 hours covers 14*20=280 deg
  ekhon,1 hour in 90 min
  thus in 90min the hour hand goes 20deg
  tai, for 1min hr hand goes 2/9deg
  sei jonne, for 40 min hour hnd goes (2/9)*40deg=80/9deg=9deg(approx)
  thus hr hand covrs total of 240+9=249deg
  now min hand covrs=40*4=160deg
  (karon, 90min=360deg
  1min=4deg)
  
  hus angle betwn them 289-160=129deg
• 13 years agoHelpfull: Yes(5) No(0)
• Angle covered by hour hand in 1 hour = 360/18 = 20 degree
  
  in one min 20/90 = 2/9 degree
  
  angle covered by minute hand in one min = 360/90 = 4 degree
  
  relative degree difference = 4 - 2/9 = 34/9
  
  now -240 + 34/9 * 40 = 88.88
  
  so 89 degree
• 13 years agoHelpfull: Yes(0) No(3)