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Numerical Ability
Number System
how many integers between 456 and 654 have no digits other than 4,5,6.
a) 15
b)17
c)14
d)12
Read Solution (Total 10)
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- first we consider when 4 is on hundreth position(456,465,466) so here 3 ways
now,when 5 is on hundreth position,tenth position is filled by 3 ways(4,5,6) & unit position is also filled by 3 ways(4,5,6), so total 3*3=9ways
when 6 is on hundreth position (644,645,646,654)
so,total integer=3+9+4=15
ans is 15
- 11 years agoHelpfull: Yes(29) No(5)
- I think its 15.
For every 2nd digit (4 or 5 or 6) we have 3 options for 3rd digit.
(464,465,466)
(544,545,546)(554,555,556)(564,565,566)
(644,645,646) - 11 years agoHelpfull: Yes(13) No(0)
- 17 will be the answer
- 11 years agoHelpfull: Yes(7) No(2)
- 6 is not the option....
correct ans is 15, bt dnt know how it came
- 11 years agoHelpfull: Yes(5) No(0)
- if we put 4 at hundred position then(455,456,465,466) 4 ways
if we put 5 as hundred then tenth position (2,3,4) 3 ways and unit is also 3 ways
so total 3*3 ways
if we put 6 as hundred then
(644,646,654,655) 4 ways
hence answer is
4+9+4=17
ans=17 - 11 years agoHelpfull: Yes(2) No(2)
- 4 at hundreth position:tens pos by 5/6(1 way), unit pos by 6 only = 1*2*1 = 2 ways
5 at hundreth pos: tens pos by 4/5/6(3ways) and unit by 3 ways =9 ways
6th at hundreth: tens by 5/4 (2 ways), unit by 4/6(2 ways) =4 ways
total integers possible = 2+9+4 = 15 ans - 11 years agoHelpfull: Yes(1) No(0)
- integers with no digits other than 4,5,6 are just the various arrangements of 456
= 3!
=6(Ans) - 11 years agoHelpfull: Yes(0) No(12)
- 15
4_ _ 3 ways
5_ _ 3*3=9 ways
6_ _ 3 ways
so total 15 ways - 11 years agoHelpfull: Yes(0) No(2)
- 3*3*3-5(for 1st 5 combination those r not taken)-5(for last 5 combination those r not taken)=17 (b) ans:
- 11 years agoHelpfull: Yes(0) No(1)
- total =17
those are 456,464,465,466,544,545,546,554,555,556,564,565,566,644,645,646,654(if 456 and 654 included)
otherwise 15. - 9 years agoHelpfull: Yes(0) No(0)
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