1. What is the side of the largest possible regular octagon that can be cut out of a square of side 1 cm?

• Let a side of Octagon be x
  Let the remaining portion of that side of square be y
  then x+2y=1 & x^2=2y^2
  Solving this two equation the result will be 0.414
• 11 years agoHelpfull: Yes(27) No(1)
• Let x be the length of the side of the octagon & y be the length of triangular piece cut from the square.
  given length of side of squous are=1
  so x+2*y=1
  in the triangle,from pythagorous theorem, y^2 + y^2 = x^2
  solving these two eqns gives x=.293 & y=.414
• 11 years agoHelpfull: Yes(21) No(1)
• the diagonal of the square will be octagon's largest possible arm so ans is =1*root(2)=1.414
• 11 years agoHelpfull: Yes(3) No(10)
• why x+2y???
• 10 years agoHelpfull: Yes(2) No(0)
• Guys link will certainly help.First go to this link to understand x & y. Then follow solution given ny @shubhajit
  
  http://mathcentral.uregina.ca/QQ/database/QQ.02.06/martin1.html
• 10 years agoHelpfull: Yes(2) No(0)
• Diagonal of the square is the largest.
  therefore,applying formula s^2=1/2d^2 where s is side and d is diagonal.
  by solving this eq we get ans:1.414
• 11 years agoHelpfull: Yes(1) No(7)
• ans will be .212 ,sorry i need digram to explain
• 11 years agoHelpfull: Yes(0) No(3)
• procedure is same as mentioned in first answer.
  answer is .293
  
• 10 years agoHelpfull: Yes(0) No(0)