Two trains for mumbai leave Delhi at 6 a.m. and 6:45 am and travel at 100 kmph and 136 kmph respectively.How many kilometers from Delhi will the two trains be together?

• 100 t =136(t-3/4)
  t=17/6
  100* 17/6 = 283.33 ans
• 11 years agoHelpfull: Yes(59) No(3)
• The slower train travels 45 minutes or 3/4 earlier. Distance travelled in 3/4 hr @ 100 km/hr = 100 × 3/4 = 75 km.
  Now let the distance travelled by slower train be x km when the two trains meet.
  So time taken by slower train to travel dist, x = x / 100 hr.
  The fast train travels a distance of ( 75 + x) km.
  Time required to travel this distance = (75 + x) / 136
  Both the times are equal.
  Therefore x / 100 = (75 + x) /136 -------- solving this
  136 x = 100 x + 7500
  36 x = 7500
  x = 7500 / 36 = 208.333
  So the trains will meet at 208.333 + 75 = 283.33 km from Delhi.
• 11 years agoHelpfull: Yes(36) No(2)
• in 45min the first train would travel 100*(45/60)=75km.
  So,the second trian would take time=(75/36)hr....... the relative speed=36.
  Therefore they would meet at (75/36)*136=283.33
• 11 years agoHelpfull: Yes(17) No(1)
• 100t=136(t-45/60)
  t=2.833 or 2:50min
  as we know dis=speed*time
  =100*2.8333
  =283.33 ans
• 11 years agoHelpfull: Yes(7) No(0)
• let total distance be=x
  x/100-x/136=45/60
  on solving,
  x=283.33km
• 10 years agoHelpfull: Yes(5) No(0)
• is it 8.47 am?
• 11 years agoHelpfull: Yes(2) No(4)
• Let the two trains meet at x hr after the departure of the first train...
  1st train covers=100*x kms
  2nd train covers=136*(x-45/60) kms
  100x=136*(x-3/4)
  x=17/6
  distance covered by the 1st train(for 2nd train its also the same)=100*17/6 kms=283.33 kms
• 11 years agoHelpfull: Yes(2) No(0)
• The slower train travels 45 minutes or 3/4hr earlier. Distance travelled in 3/4 hr @ 100 km/hr = 100 × 3/4 = 75 km. now by applying relative motion formula we have 75/(136-100)=75/36=2.833.. i.e after 2.833 hrs the two trains wil meet and the distance travelled by slower train in 2.833 hrs is 100*2.833=283.33 km from delhi the trains will meet together..
  
• 11 years agoHelpfull: Yes(1) No(0)
• is it 6 p.m.?
• 11 years agoHelpfull: Yes(0) No(5)
• OHH SORRY...ITS 8.50 am...
• 11 years agoHelpfull: Yes(0) No(5)
• distance traveled by first train in the first 45 min = 100*45/60
  
  to meet it the second train will have to cover the above distance at relative speed of 36km/h
  therefore
  
  t= (100*45/60)/36 ...............(1)
  
  distance at which they meet = (1)*136km/hr
  
  d=550m
• 11 years agoHelpfull: Yes(0) No(4)
• in 45 min the first train would travel 100*(45/60)=75 km.
  So,the second train would take time=(75/36)hr....... the relative speed=36kmph.
  Therefore they would meet at (75/36)*136=283.33km
• 11 years agoHelpfull: Yes(0) No(0)
• ans=285.6km
• 11 years agoHelpfull: Yes(0) No(1)
• Distance already covered by train which left delhi at 6am= 100km/hr * 45/60hrs = 75km.
  relative speed of the two trains= (136-130)km/hr = 36.
  therefore, distance of the two trains from delhi =time*speed
  = * speed of the 2nd train)
  = (75km/36km/hr)*136km/hr= 283.33km
• 11 years agoHelpfull: Yes(0) No(0)
• 283.33 km from delhi.
• 11 years agoHelpfull: Yes(0) No(0)