There is a three digit number , such that third digit is square of first digit.find the probability that the number is divisible by 2 ,3 or 5?

• case 1) 1_1 only three no. / by 3 i.e 111,141,171 (total 3)
  case 2) 2_4 here all no. / by 2(total 10)
  case 3) 3_9 only 3 no. / by 3 i.e 309,339,369,399 (total 4)
  
  so prob. will be 17/30
• 11 years agoHelpfull: Yes(21) No(7)
• you are not write complete question.. you forget this line ..repeated digit not allowed in the number..and number is not divisible by 2,3,5
• 11 years agoHelpfull: Yes(5) No(0)
• 21/30 = 7/10
  
• 11 years agoHelpfull: Yes(2) No(1)
• ans will be 8/15
• 11 years agoHelpfull: Yes(1) No(4)
• 3/8
  in b/n 2 and 4 eight no can be putted & in between 3 and 9 also eight value can be putted. so sample space is 16.
  in case of 2-4 no any value which no divisible by 2,3 and 5,,,,,,,,
  in case of 3-9 when putting 1,2,4,5,7,8 not divisible by 2,3 and 5
  
  
  so ans will be 6/16
• 11 years agoHelpfull: Yes(1) No(3)
• There is a three digit number , such that third digit is square of first digit .repeated digit not allowed in the number..and number is not divisible by 2,3,5...
• 11 years agoHelpfull: Yes(0) No(1)
• 3/4
  total no formed=24
  divisible by 2,3 or 5=18
  so prob=18/24=3/4
• 11 years agoHelpfull: Yes(0) No(1)
• i am not getting the logic behind the answers given can anybody help
  
• 11 years agoHelpfull: Yes(0) No(0)
• 1/3 i think
  
• 11 years agoHelpfull: Yes(0) No(0)
• answer will be
  1-(17/30)=13/30
• 11 years agoHelpfull: Yes(0) No(1)