50!/(15)^16
what is the remainder

• 50!=2^47*3^22*5^12*...*47
  (15)^16=3^16*5^16
  50!/(15)^16=2^47*3^6*...*47/5^4
  unit place will be 2^47*3^14*7^12*9/5^4
  8*9*1*9/5^4
  or 8/5
  so remainder will be 3
• 10 years agoHelpfull: Yes(1) No(0)
• 50! has 0 at the unit digit 15 power divisible by it
• 10 years agoHelpfull: Yes(0) No(0)
• zero
  because 50! have zero at last digit and 15^16 have 5 at last digit
  hence 50!/(15)^16 is completely divisible
• 9 years agoHelpfull: Yes(0) No(0)
• zero
  because 50! have zero at last digit and 15^16 have 5 at last digit
  
• 9 years agoHelpfull: Yes(0) No(0)