The base of a right pyramid is an equilateral triangle of side 10(3)^1/3cm.if total surface area of the pyramid is 270(3)^1/3 sq. cm,its height is

• we know the area of a pyramid b2+4(bh/2),
  here given that pyramid is an equilateral triangle of side 10(3)^1/3cm,
  let height of the pyramid is h
  so, (10(3)^1/3)^1/2+4*((10(3)^3 *h)/2)=270(3)^1/3
  by calculating we get h=6.28cm
  
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• 
  4*2*10(3)^1/3*h=270(3)^1/3
  h=3.37cm
• 10 years agoHelpfull: Yes(0) No(0)