if there are 6 balls in which 5 wt same and 1 weight slightly more...explain how we find heaviest nd how many turns??

• it will take only 2 turns, first 3 balls on a side & 3 at other side, then from heavier side put one ball at one side and 2nd ball another side. either one of them is heavier otherwise the remaining of them is heavier
  So, only 2 turns
• 10 years agoHelpfull: Yes(23) No(2)
• in 2 turns
  I) First weight with 3-3 each in balance, heavier 3 will be known
  II)Among 3 keep 1-1 in balance,heavier can be known,if equal in weight then remaining is the heavier.
  
• 10 years agoHelpfull: Yes(17) No(0)
• In minimum 2 ways it can be done
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• In two turns
• 10 years agoHelpfull: Yes(0) No(0)
• now do it for 8 balls in 3 turns.good puzzle anyway to solve
  
• 10 years agoHelpfull: Yes(0) No(0)
• in minimum 2 ways
  first make a 3 groups each having 2 balls
  compare any 2 groups if there is an imbalance then you would get the heavier group else third group would be heavier
  
  then from the heaviest group weigh the two balls....you would easily find the heaviest ball..in only two comparisons
• 10 years agoHelpfull: Yes(0) No(0)