Find last digit.(1023^3923)+(3087^3927)

• The solution can derived as:
  3923 % 4=3
  3927 % 4=3 (also)
  
  Now last digit of 1023 is 3, so 3^3923->3^(3923 % 4)->3^3=27(take last digit i.e 7)
  Similarly,last digit of 3087 is 7, so 7^3927->7^(3923 % 4)->7^3=343(take last digit i.e 3)
  
  Add 7+3= 10
  (Take last digit of 10 i.e. 0)
  
  Thus, the answer is 0.
  
• 11 years agoHelpfull: Yes(29) No(0)
• last digit of the exp will be same as the last digit of 3^3923 + 7^3927
  3923=4*980+3 & 3927=4*981+3 so last digit of 3^3923 + 7^3927=last digit of 3^3 + 7^3
  i.e 27+343
  hence unit digit will be 7+3=10
  ans is zero
  
• 11 years agoHelpfull: Yes(4) No(0)
• 3^3+7^7
  =7+3
  =10
  so last digit of this equation is 0
• 11 years agoHelpfull: Yes(1) No(0)
• ans: 0
  3^3=81 2*3=6
  7^7=49 8*7=56
  
  681+5649=last digit comes to 0
• 11 years agoHelpfull: Yes(0) No(0)
• 3^3923+7^3927=7+3=0
  
• 11 years agoHelpfull: Yes(0) No(0)
• 1023^3923= 7 last digit
  3087^3927= 3 last digit
  therefore,last digit is 0.
• 11 years agoHelpfull: Yes(0) No(0)
• last digit will be :: 0
• 11 years agoHelpfull: Yes(0) No(0)
• last digit is 0
• 11 years agoHelpfull: Yes(0) No(0)
• 0 i s the answer !!!
• 11 years agoHelpfull: Yes(0) No(0)