The two digits are selected at random from the digits 1 through 9. If the sum of the two digits is even, find the probability that both numbers are odd.

• the probability that both numbers are odd=5C2/9C2
  =5/18
• 10 years agoHelpfull: Yes(1) No(1)
• answer is 1/4....
  (always)sum is either even or odd
  probability of sum is even==> 1/2
  sum is even has two cond (always)
  1. two digits are even
  2. two digits are odd
  therfore probability for even sum with both numbers odd ===> ((1/2)/2) = 1/4
• 10 years agoHelpfull: Yes(1) No(2)