If two men stand back to back, walk in opposite directions for 4 metres, turn to the left and walk another 3 metres, what is the distance between them when they stop?

• 10 meters
  Distance= 2*(hypotenuse of right angled triangle with side 4m. and 3 m.)
  =2*Sqrt(4^2+3^2)=2*5= 10
  
• 11 years agoHelpfull: Yes(39) No(0)
• let they started travel from (0,0) along +ve and -ve x-axis
  their final position will be (-4,-3) & (4,3)
  so distance betn two can be calculated by distance formula
  d=sqroot[(4+4)^2 + (3+3)^2]=10 metres
  
  or,sketch their path
  d=2*Sqrt(4^2+3^2)=2*5= 10
• 11 years agoHelpfull: Yes(18) No(1)
• back to back.. so they travelled 4m in straight and left by 3m. so they changed to opppsite drn on taking left. so by pythagorous theorem 5 + 5 m are left between them. so answer is 10m
• 11 years agoHelpfull: Yes(6) No(1)
• guys...we 've 2 find distance between them....Distance is 14mts and displacement is 10 mts...i think....??
  
• 11 years agoHelpfull: Yes(5) No(4)
• ans- 14 mts
  
• 11 years agoHelpfull: Yes(3) No(9)
• here,w'll get 2 Rtriangles,
  distance=hyp1+hyp2.
  hyp1=sqt(4^2+3^2)=5;
  hyp2=sqt(4^2+3^2)=5;
  so,d=10m
• 11 years agoHelpfull: Yes(1) No(1)
• using pythogores we can solve tis
  ans: 10
• 11 years agoHelpfull: Yes(1) No(1)
• 10 meters.
  travelled 4m in straight and left by 3m.
  then we get 2 triangles. for each,hypo is 5m so ans is 10.
  
• 11 years agoHelpfull: Yes(1) No(1)
• apply pythagorus rule a = sqrt(b^2 + c^2)
  a = sqrt(4^2 + 3^2)
  a = sqrt (16 + 9)
  a = sqrt(25)
  a = 5
  then tat side also same 5 + 5 = 10
  ans 10
• 11 years agoHelpfull: Yes(1) No(1)
• 
  sqrt(8^2+6^2)=10 meters
  
• 11 years agoHelpfull: Yes(0) No(0)
• drw the diagram and according to it ans is 7.2
• 11 years agoHelpfull: Yes(0) No(2)
• 10 is the ans
  
• 11 years agoHelpfull: Yes(0) No(0)
• 10 m ...use
• 10 years agoHelpfull: Yes(0) No(0)
• 10 is d rit ans...
  
• 10 years agoHelpfull: Yes(0) No(0)
• By using pythagorus 10 meter is right answer
• 10 years agoHelpfull: Yes(0) No(0)